Python

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树时的问题

1. python中对象的基本组成_valives的博客-CSDN博客 (opens new window)
2. Python打印对象的全部属性_Ricky的技术小站的博客-CSDN博客_python输出对象所有属性 (opens new window)

a = [i for i in range(5) if i > 2 ]

print(a)

python中参数列表的形式

a, b
a=1, b=2
*args
**kwargs
a, b=1, *args
空
......

list中sort方法

cut_dimensions.sort(key=lambda i: \
            (-distinct_components_count[i], -distinct_components_ratio[i]))

[476, 94, 1, 21, 5, 0, 11, 33, 0, 0, 0, 0, 0, 1, 13, 25]
0 0
[477, 94, 1, 21, 5, 0, 11, 33, 0, 0, 0, 0, 0, 1, 13, 25]
0 0
[478, 94, 1, 21, 5, 0, 11, 33, 0, 0, 0, 0, 0, 1, 13, 25]
cut_nums== [8, 8]
total_cuts== 64 # 8*8=64
[1, 3] [8, 8] #dim 1 3; cuts: 8 8

[0, 1, 3]
distinct_components_count== [18, 17, 1, 20, 1] distinct_components_ratio== [1.2240012578816128e-08, 2.439231567444466e-06, 1.52587890625e-05, 0.041928721174004195, 1.0]
(-1, -1.0)
2=== [3, 0, 1]

last_mean== 49
cut_nums== [8]
total_cuts== 8

last_mean== 49
cut_nums== [8, 2]
total_cuts== 16

last_mean== 49
cut_nums== [8, 2, 1]
total_cuts== 16

[3, 0] [8, 2]